Matematika Sekolah Menengah Atas Kuis +50
√√(331.776) × √√(65.536) ÷ √√(20.736) = 2ⁿ
n = ......

Kuis +50
√√(331.776) × √√(65.536) ÷ √√(20.736) = 2ⁿ
n = ......

Penyelesaian

  • [tex] \footnotesize \sf \sqrt{ \sqrt{(331.776)} } \times \sqrt{ \sqrt{(65.536)} } \div \sqrt{ \sqrt{(20.736)} } = {2}^{n} [/tex]

Nilai n adalah ...

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[tex]\sf \sqrt{ \sqrt{(331.776)} } \times \sqrt{ \sqrt{(65.536)} } \div \sqrt{ \sqrt{(20.736)} } = {2}^{n} [/tex]

[tex] \sf \sqrt{ \sqrt{ {576}^{2} } } \times \sqrt{ \sqrt{ {256}^{2} } } \div \sqrt{ \sqrt{ {144}^{2} } } = {2}^{n} [/tex]

[tex] \sf \sqrt{576} \times \sqrt{256} \div \sqrt{144} = {2}^{n} [/tex]

[tex] \sf \sqrt{ {24}^{2} } \times \sqrt{ {16}^{2} } \div \sqrt{ {12}^{2} } = {2}^{n} [/tex]

[tex] \sf24 \times 16 \div 12 = {2}^{n} [/tex]

[tex] \sf384 \div 12 = {2}^{n} [/tex]

[tex] \sf32 = {2}^{n} [/tex]

[tex] \sf { \cancel2}^{5} = { \cancel2}^{n} [/tex]

[tex]\sf 5 = n[/tex]

[tex]\bf n = 5[/tex]

[tex]\\[/tex]

[tex] \huge \tt{ \color{ff2000}{@} \color{ff5000}{N}} \color{ff8000}{o} \color{ffdd00}{t} \color{fbf500}{L} \color{ddff00}{i} \color{bdff00}{x} \color{5dff00}{z} \color{00ffd5}{⌫}[/tex]

  • √√331.776 × √√65.536 ÷ √√20.736 = 2ⁿ
  • √576 × √256 ÷ √144 = 2ⁿ
  • 24 × 16 ÷ 12 = 2ⁿ
  • 384 ÷ 12 = 2ⁿ
  • 32 = 2ⁿ
  • 2⁵ = 2ⁿ
  • n = 5

[tex]\boxed{\colorbox{purple}{ \colorbox{pink}{ \bf{NanazCanss< 3}}}}[/tex]

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